35b^2-37b-6=0

Solution for 35b^2-37b-6=0 equation:

35b^2-37b-6=0

a = 35; b = -37; c = -6;
Δ = b2-4ac
Δ = -372-4·35·(-6)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-47}{2*35}=\frac{-10}{70}
=-1/7
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+47}{2*35}=\frac{84}{70}
=1+1/5
$